Base | Representation |
---|---|
bin | 11101110011111001111010… |
… | …000110001110011011100111 |
3 | 122012020000101200001110020202 |
4 | 131303321322012032123213 |
5 | 114141102212323130043 |
6 | 1142503111552221115 |
7 | 36421254323125451 |
oct | 3563717206163347 |
9 | 565200350043222 |
10 | 131110220130023 |
11 | 38859594255172 |
12 | 1285605753a79b |
13 | 5820843832574 |
14 | 2453aa8b2b2d1 |
15 | 10257273db1b8 |
hex | 773e7a18e6e7 |
131110220130023 has 4 divisors (see below), whose sum is σ = 131110262999040. Its totient is φ = 131110177261008.
The previous prime is 131110220130013. The next prime is 131110220130107. The reversal of 131110220130023 is 320031022011131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131110220130023 - 24 = 131110220130007 is a prime.
It is a super-3 number, since 3×1311102201300233 (a number of 43 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131110220129977 and 131110220130004.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131110220130013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16462478 + ... + 23091851.
It is an arithmetic number, because the mean of its divisors is an integer number (32777565749760).
Almost surely, 2131110220130023 is an apocalyptic number.
131110220130023 is a deficient number, since it is larger than the sum of its proper divisors (42869017).
131110220130023 is an equidigital number, since it uses as much as digits as its factorization.
131110220130023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 42869016.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 131110220130023 its reverse (320031022011131), we get a palindrome (451141242141154).
The spelling of 131110220130023 in words is "one hundred thirty-one trillion, one hundred ten billion, two hundred twenty million, one hundred thirty thousand, twenty-three".
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