Base | Representation |
---|---|
bin | 10011000101000011110… |
… | …011101011011101101001 |
3 | 11122100011222221022110202 |
4 | 103011003303223131221 |
5 | 132440114234133441 |
6 | 2442151235521545 |
7 | 163503226420142 |
oct | 23050363533551 |
9 | 4570158838422 |
10 | 1311102646121 |
11 | 466043299594 |
12 | 1921257592b5 |
13 | 96837380b28 |
14 | 47659d38ac9 |
15 | 241889dd19b |
hex | 13143ceb769 |
1311102646121 has 2 divisors, whose sum is σ = 1311102646122. Its totient is φ = 1311102646120.
The previous prime is 1311102646093. The next prime is 1311102646153. The reversal of 1311102646121 is 1216462011131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1269757117225 + 41345528896 = 1126835^2 + 203336^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311102646121 - 238 = 1036224739177 is a prime.
It is not a weakly prime, because it can be changed into another prime (1311102246121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655551323060 + 655551323061.
It is an arithmetic number, because the mean of its divisors is an integer number (655551323061).
Almost surely, 21311102646121 is an apocalyptic number.
It is an amenable number.
1311102646121 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311102646121 is an equidigital number, since it uses as much as digits as its factorization.
1311102646121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 29.
Adding to 1311102646121 its reverse (1216462011131), we get a palindrome (2527564657252).
The spelling of 1311102646121 in words is "one trillion, three hundred eleven billion, one hundred two million, six hundred forty-six thousand, one hundred twenty-one".
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