Search a number
-
+
131110420040147 is a prime number
BaseRepresentation
bin11101110011111010000110…
…000000110100100111010011
3122012020000220121012221101102
4131303322012000310213103
5114141103120012241042
61142503143453055015
736421262301260012
oct3563720600644723
9565200817187342
10131110420040147
1138859687086649
12128560b248746b
135820876087992
142453ac74c8a79
151025739c28b32
hex773e860349d3

131110420040147 has 2 divisors, whose sum is σ = 131110420040148. Its totient is φ = 131110420040146.

The previous prime is 131110420040107. The next prime is 131110420040153. The reversal of 131110420040147 is 741040024011131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131110420040147 - 238 = 130835542133203 is a prime.

It is not a weakly prime, because it can be changed into another prime (131110420040107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555210020073 + 65555210020074.

It is an arithmetic number, because the mean of its divisors is an integer number (65555210020074).

Almost surely, 2131110420040147 is an apocalyptic number.

131110420040147 is a deficient number, since it is larger than the sum of its proper divisors (1).

131110420040147 is an equidigital number, since it uses as much as digits as its factorization.

131110420040147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2688, while the sum is 29.

Adding to 131110420040147 its reverse (741040024011131), we get a palindrome (872150444051278).

The spelling of 131110420040147 in words is "one hundred thirty-one trillion, one hundred ten billion, four hundred twenty million, forty thousand, one hundred forty-seven".