13111043310313 has 4 divisors (see below), whose sum is σ = 14119585103428. Its totient is φ = 12102501517200.

The previous prime is 13111043310307. The next prime is 13111043310331. The reversal of 13111043310313 is 31301334011131.

13111043310313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1280525349609 + 11830517960704 = 1131603^2 + 3439552^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111043310313 - 2¹³ = 13111043302121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13111043317313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504270896538 + ... + 504270896563.

It is an arithmetic number, because the mean of its divisors is an integer number (3529896275857).

Almost surely, 2^{13111043310313} is an apocalyptic number.

13111043310313 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13111043310313 is a deficient number, since it is larger than the sum of its proper divisors (1008541793115).

13111043310313 is a wasteful number, since it uses less digits than its factorization.

13111043310313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1008541793114.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 13111043310313 its reverse (31301334011131), we get a palindrome (44412377321444).

The spelling of 13111043310313 in words is "thirteen trillion, one hundred eleven billion, forty-three million, three hundred ten thousand, three hundred thirteen".