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13111100201057 is a prime number
BaseRepresentation
bin1011111011001010101001…
…1110000101100001100001
31201102102001010010111202212
42332302222132011201201
53204303013122413212
643515053431251505
72522150166623165
oct276625236054141
951372033114685
1013111100201057
1141a5428292181
121579028b19b95
137414aa0a6661
1433481b39aca5
1517b0b3154e22
hexbecaa785861

13111100201057 has 2 divisors, whose sum is σ = 13111100201058. Its totient is φ = 13111100201056.

The previous prime is 13111100201047. The next prime is 13111100201071. The reversal of 13111100201057 is 75010200111131.

13111100201057 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9211170370081 + 3899929830976 = 3034991^2 + 1974824^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111100201057 - 24 = 13111100201041 is a prime.

It is not a weakly prime, because it can be changed into another prime (13111100201047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555550100528 + 6555550100529.

It is an arithmetic number, because the mean of its divisors is an integer number (6555550100529).

Almost surely, 213111100201057 is an apocalyptic number.

It is an amenable number.

13111100201057 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111100201057 is an equidigital number, since it uses as much as digits as its factorization.

13111100201057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 210, while the sum is 23.

Adding to 13111100201057 its reverse (75010200111131), we get a palindrome (88121300312188).

The spelling of 13111100201057 in words is "thirteen trillion, one hundred eleven billion, one hundred million, two hundred one thousand, fifty-seven".