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13111102241 is a prime number
BaseRepresentation
bin11000011010111101…
…11000101100100001
31020211201212000002022
430031132320230201
5203322420232431
610005000231225
7642622346606
oct141536705441
936751760068
1013111102241
11561896a196
12265aa6b515
13130c401983
148c540a6ad
1551b09b07b
hex30d7b8b21

13111102241 has 2 divisors, whose sum is σ = 13111102242. Its totient is φ = 13111102240.

The previous prime is 13111102163. The next prime is 13111102261. The reversal of 13111102241 is 14220111131.

13111102241 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13073635600 + 37466641 = 114340^2 + 6121^2 .

It is an emirp because it is prime and its reverse (14220111131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111102241 - 222 = 13106907937 is a prime.

It is not a weakly prime, because it can be changed into another prime (13111102261) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555551120 + 6555551121.

It is an arithmetic number, because the mean of its divisors is an integer number (6555551121).

Almost surely, 213111102241 is an apocalyptic number.

It is an amenable number.

13111102241 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111102241 is an equidigital number, since it uses as much as digits as its factorization.

13111102241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 13111102241 its reverse (14220111131), we get a palindrome (27331213372).

The spelling of 13111102241 in words is "thirteen billion, one hundred eleven million, one hundred two thousand, two hundred forty-one".