13111103014001 has 2 divisors, whose sum is σ = 13111103014002. Its totient is φ = 13111103014000.

The previous prime is 13111103013979. The next prime is 13111103014033. The reversal of 13111103014001 is 10041030111131.

13111103014001 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13053299314225 + 57803699776 = 3612935^2 + 240424^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111103014001 - 2³⁴ = 13093923144817 is a prime.

It is a super-2 number, since 2×13111103014001² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13111103014081) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555551507000 + 6555551507001.

It is an arithmetic number, because the mean of its divisors is an integer number (6555551507001).

Almost surely, 2^{13111103014001} is an apocalyptic number.

It is an amenable number.

13111103014001 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111103014001 is an equidigital number, since it uses as much as digits as its factorization.

13111103014001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 13111103014001 its reverse (10041030111131), we get a palindrome (23152133125132).

The spelling of 13111103014001 in words is "thirteen trillion, one hundred eleven billion, one hundred three million, fourteen thousand, one".