Base | Representation |
---|---|
bin | 1011111011001010101010… |
… | …1001101001110011101011 |
3 | 1201102102001022211120011122 |
4 | 2332302222221221303223 |
5 | 3204303014411431014 |
6 | 43515054020245455 |
7 | 2522150234452343 |
oct | 276625251516353 |
9 | 51372038746148 |
10 | 13111103233259 |
11 | 41a5429a73329 |
12 | 1579029b4088b |
13 | 7414aa8c8865 |
14 | 33481b949d23 |
15 | 17b0b355358e |
hex | becaaa69ceb |
13111103233259 has 2 divisors, whose sum is σ = 13111103233260. Its totient is φ = 13111103233258.
The previous prime is 13111103233181. The next prime is 13111103233273. The reversal of 13111103233259 is 95233230111131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13111103233259 is a prime.
It is a super-2 number, since 2×131111032332592 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13111103233759) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555551616629 + 6555551616630.
It is an arithmetic number, because the mean of its divisors is an integer number (6555551616630).
Almost surely, 213111103233259 is an apocalyptic number.
13111103233259 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111103233259 is an equidigital number, since it uses as much as digits as its factorization.
13111103233259 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14580, while the sum is 35.
The spelling of 13111103233259 in words is "thirteen trillion, one hundred eleven billion, one hundred three million, two hundred thirty-three thousand, two hundred fifty-nine".
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