13111103404143 has 12 divisors (see below), whose sum is σ = 18940534354560. Its totient is φ = 8739686118816.

The previous prime is 13111103404129. The next prime is 13111103404153. The reversal of 13111103404143 is 34140430111131.

13111103404143 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 110 + 3 + 404 + 143 = 666.

It is not a de Polignac number, because 13111103404143 - 2⁵ = 13111103404111 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111103404153) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 87377871 + ... + 87527792.

It is an arithmetic number, because the mean of its divisors is an integer number (1578377862880).

Almost surely, 2^{13111103404143} is an apocalyptic number.

13111103404143 is a deficient number, since it is larger than the sum of its proper divisors (5829430950417).

13111103404143 is a wasteful number, since it uses less digits than its factorization.

13111103404143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 174913998 (or 174913995 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 27.

Adding to 13111103404143 its reverse (34140430111131), we get a palindrome (47251533515274).

The spelling of 13111103404143 in words is "thirteen trillion, one hundred eleven billion, one hundred three million, four hundred four thousand, one hundred forty-three".