13111103404153 has 2 divisors, whose sum is σ = 13111103404154. Its totient is φ = 13111103404152.

The previous prime is 13111103404129. The next prime is 13111103404193. The reversal of 13111103404153 is 35140430111131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7935646752784 + 5175456651369 = 2817028^2 + 2274963^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111103404153 - 2⁴¹ = 10912080148601 is a prime.

It is not a weakly prime, because it can be changed into another prime (13111103404193) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555551702076 + 6555551702077.

It is an arithmetic number, because the mean of its divisors is an integer number (6555551702077).

Almost surely, 2^{13111103404153} is an apocalyptic number.

It is an amenable number.

13111103404153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111103404153 is an equidigital number, since it uses as much as digits as its factorization.

13111103404153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 28.

Adding to 13111103404153 its reverse (35140430111131), we get a palindrome (48251533515284).

The spelling of 13111103404153 in words is "thirteen trillion, one hundred eleven billion, one hundred three million, four hundred four thousand, one hundred fifty-three".