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1311111020137 is a prime number
BaseRepresentation
bin10011000101000100010…
…011100111111001101001
311122100012120200202110111
4103011010103213321221
5132440123410121022
62442152135214321
7163503360535162
oct23050423477151
94570176622414
101311111020137
11466047a99066
121921285173a1
1396839023579
144765b0b8769
15241895e4477
hex131444e7e69

1311111020137 has 2 divisors, whose sum is σ = 1311111020138. Its totient is φ = 1311111020136.

The previous prime is 1311111020123. The next prime is 1311111020147. The reversal of 1311111020137 is 7310201111131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1281380984361 + 29730035776 = 1131981^2 + 172424^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311111020137 - 211 = 1311111018089 is a prime.

It is not a weakly prime, because it can be changed into another prime (1311111020147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655555510068 + 655555510069.

It is an arithmetic number, because the mean of its divisors is an integer number (655555510069).

Almost surely, 21311111020137 is an apocalyptic number.

It is an amenable number.

1311111020137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311111020137 is an equidigital number, since it uses as much as digits as its factorization.

1311111020137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 22.

Adding to 1311111020137 its reverse (7310201111131), we get a palindrome (8621312131268).

The spelling of 1311111020137 in words is "one trillion, three hundred eleven billion, one hundred eleven million, twenty thousand, one hundred thirty-seven".