Base | Representation |
---|---|
bin | 11000011010111101… |
… | …11010110110001011 |
3 | 1020211201212110011121 |
4 | 30031132322312023 |
5 | 203322421023201 |
6 | 10005000340111 |
7 | 642622414363 |
oct | 141536726613 |
9 | 36751773147 |
10 | 13111111051 |
11 | 5618975875 |
12 | 265aa74637 |
13 | 130c40599c |
14 | 8c540d9a3 |
15 | 51b09d9a1 |
hex | 30d7bad8b |
13111111051 has 2 divisors, whose sum is σ = 13111111052. Its totient is φ = 13111111050.
The previous prime is 13111111007. The next prime is 13111111099. The reversal of 13111111051 is 15011111131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13111111051 - 217 = 13110979979 is a prime.
It is not a weakly prime, because it can be changed into another prime (13111181051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555555525 + 6555555526.
It is an arithmetic number, because the mean of its divisors is an integer number (6555555526).
Almost surely, 213111111051 is an apocalyptic number.
13111111051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111111051 is an equidigital number, since it uses as much as digits as its factorization.
13111111051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 16.
Adding to 13111111051 its reverse (15011111131), we get a palindrome (28122222182).
The spelling of 13111111051 in words is "thirteen billion, one hundred eleven million, one hundred eleven thousand, fifty-one".
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