Base | Representation |
---|---|
bin | 11101110011111010110000… |
… | …010101111100100111111011 |
3 | 122012020002202002112212102212 |
4 | 131303322300111330213323 |
5 | 114141111043314033201 |
6 | 1142503342142445335 |
7 | 36421316013563201 |
oct | 3563726025744773 |
9 | 565202662485385 |
10 | 131111130221051 |
11 | 38859a10a4a012 |
12 | 1285627029384b |
13 | 582095a250076 |
14 | 2453b53953071 |
15 | 102577c25cabb |
hex | 773eb057c9fb |
131111130221051 has 2 divisors, whose sum is σ = 131111130221052. Its totient is φ = 131111130221050.
The previous prime is 131111130220997. The next prime is 131111130221059. The reversal of 131111130221051 is 150122031111131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131111130221051 is a prime.
It is not a weakly prime, because it can be changed into another prime (131111130221059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65555565110525 + 65555565110526.
It is an arithmetic number, because the mean of its divisors is an integer number (65555565110526).
Almost surely, 2131111130221051 is an apocalyptic number.
131111130221051 is a deficient number, since it is larger than the sum of its proper divisors (1).
131111130221051 is an equidigital number, since it uses as much as digits as its factorization.
131111130221051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 180, while the sum is 23.
Adding to 131111130221051 its reverse (150122031111131), we get a palindrome (281233161332182).
The spelling of 131111130221051 in words is "one hundred thirty-one trillion, one hundred eleven billion, one hundred thirty million, two hundred twenty-one thousand, fifty-one".
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