| Base | Representation |
|---|---|
| bin | 1011111011001010101100… |
| … | …1111010101111000100000 |
| 3 | 1201102102002000102111210102 |
| 4 | 2332302223033111320200 |
| 5 | 3204303024424104440 |
| 6 | 43515055012121532 |
| 7 | 2522150414441531 |
| oct | 276625317257040 |
| 9 | 51372060374712 |
| 10 | 13111113113120 |
| 11 | 41a5434601200 |
| 12 | 15790313062a8 |
| 13 | 7414ac977829 |
| 14 | 33481cd9c688 |
| 15 | 17b0b4355b15 |
| hex | becab3d5e20 |
13111113113120 has 288 divisors, whose sum is σ = 34590757840128. Its totient is φ = 4692089600000.
The previous prime is 13111113113117. The next prime is 13111113113201. The reversal of 13111113113120 is 2131131111131.
It is a super-2 number, since 2×131111131131202 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 13111113113092 and 13111113113101.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 326525045 + ... + 326565195.
It is an arithmetic number, because the mean of its divisors is an integer number (120106798056).
Almost surely, 213111113113120 is an apocalyptic number.
13111113113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13111113113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17295378920064).
13111113113120 is an abundant number, since it is smaller than the sum of its proper divisors (21479644727008).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111113113120 is a wasteful number, since it uses less digits than its factorization.
13111113113120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 40456 (or 40437 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 20.
Adding to 13111113113120 its reverse (2131131111131), we get a palindrome (15242244224251).
It can be divided in two parts, 131111 and 13113120, that added together give a palindrome (13244231).
The spelling of 13111113113120 in words is "thirteen trillion, one hundred eleven billion, one hundred thirteen million, one hundred thirteen thousand, one hundred twenty".
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