Base | Representation |
---|---|
bin | 1011111011001010101110… |
… | …1010000111100000110000 |
3 | 1201102102002111122010002021 |
4 | 2332302223222013200300 |
5 | 3204303033223212034 |
6 | 43515055422401224 |
7 | 2522150531214256 |
oct | 276625352074060 |
9 | 51372074563067 |
10 | 13111120132144 |
11 | 41a5438565751 |
12 | 1579033730214 |
13 | 7414b12645b8 |
14 | 33481dca85d6 |
15 | 17b0b4c906b4 |
hex | becaba87830 |
13111120132144 has 20 divisors (see below), whose sum is σ = 25404494789520. Its totient is φ = 6555121476800.
The previous prime is 13111120132133. The next prime is 13111120132169. The reversal of 13111120132144 is 44123102111131.
13111120132144 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-4 number, since 4×131111201321444 (a number of 54 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27165139 + ... + 27643570.
It is an arithmetic number, because the mean of its divisors is an integer number (1270224739476).
Almost surely, 213111120132144 is an apocalyptic number.
It is an amenable number.
13111120132144 is a deficient number, since it is larger than the sum of its proper divisors (12293374657376).
13111120132144 is a wasteful number, since it uses less digits than its factorization.
13111120132144 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54823668 (or 54823662 counting only the distinct ones).
The product of its (nonzero) digits is 576, while the sum is 25.
Adding to 13111120132144 its reverse (44123102111131), we get a palindrome (57234222243275).
The spelling of 13111120132144 in words is "thirteen trillion, one hundred eleven billion, one hundred twenty million, one hundred thirty-two thousand, one hundred forty-four".
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