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131111203130000 = 2454293919115363
BaseRepresentation
bin11101110011111010110100…
…101100000100101010010000
3122012020002221011202000201022
4131303322310230010222100
5114141111221000130000
61142503353305255012
736421320560363552
oct3563726454045220
9565202834660638
10131111203130000
1138859a49117645
1212856290794468
13582096c399962
142453b5d4d14d2
151025783860585
hex773eb4b04a90

131111203130000 has 200 divisors, whose sum is σ = 328465949750400. Its totient is φ = 50622691392000.

The previous prime is 131111203129981. The next prime is 131111203130009. The reversal of 131111203130000 is 31302111131.

It is a tau number, because it is divible by the number of its divisors (200).

It is a super-2 number, since 2×1311112031300002 (a number of 29 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (131111203130009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 1136452319 + ... + 1136567681.

It is an arithmetic number, because the mean of its divisors is an integer number (1642329748752).

Almost surely, 2131111203130000 is an apocalyptic number.

131111203130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131111203130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (164232974875200).

131111203130000 is an abundant number, since it is smaller than the sum of its proper divisors (197354746620400).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131111203130000 is a wasteful number, since it uses less digits than its factorization.

131111203130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 119339 (or 119318 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 131111203130000 its reverse (31302111131), we get a palindrome (131142505241131).

The spelling of 131111203130000 in words is "one hundred thirty-one trillion, one hundred eleven billion, two hundred three million, one hundred thirty thousand".