131111354541 has 4 divisors (see below), whose sum is σ = 174815139392. Its totient is φ = 87407569692.

The previous prime is 131111354519. The next prime is 131111354581. The reversal of 131111354541 is 145453111131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 131111354541 - 2¹³ = 131111346349 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 131111354499 and 131111354508.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131111354501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21851892421 + ... + 21851892426.

It is an arithmetic number, because the mean of its divisors is an integer number (43703784848).

Almost surely, 2^131111354541 is an apocalyptic number.

It is an amenable number.

131111354541 is a deficient number, since it is larger than the sum of its proper divisors (43703784851).

131111354541 is an equidigital number, since it uses as much as digits as its factorization.

131111354541 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43703784850.

The product of its digits is 3600, while the sum is 30.

Adding to 131111354541 its reverse (145453111131), we get a palindrome (276564465672).

The spelling of 131111354541 in words is "one hundred thirty-one billion, one hundred eleven million, three hundred fifty-four thousand, five hundred forty-one".