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1311114923 is a prime number
BaseRepresentation
bin100111000100110…
…0000011010101011
310101101002112112222
41032021200122223
510141121134143
6334033424255
744330202326
oct11611403253
93341075488
101311114923
116130aa058
1230710b08b
1317b82a161
14c61b57bd
157a188768
hex4e2606ab

1311114923 has 2 divisors, whose sum is σ = 1311114924. Its totient is φ = 1311114922.

The previous prime is 1311114881. The next prime is 1311114929. The reversal of 1311114923 is 3294111131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1311114923 - 28 = 1311114667 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311114892 and 1311114901.

It is not a weakly prime, because it can be changed into another prime (1311114929) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655557461 + 655557462.

It is an arithmetic number, because the mean of its divisors is an integer number (655557462).

Almost surely, 21311114923 is an apocalyptic number.

1311114923 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311114923 is an equidigital number, since it uses as much as digits as its factorization.

1311114923 is an evil number, because the sum of its binary digits is even.

The product of its digits is 648, while the sum is 26.

The square root of 1311114923 is about 36209.3209408848. The cubic root of 1311114923 is about 1094.4945083825.

The spelling of 1311114923 in words is "one billion, three hundred eleven million, one hundred fourteen thousand, nine hundred twenty-three".