13111213130011 has 2 divisors, whose sum is σ = 13111213130012. Its totient is φ = 13111213130010.

The previous prime is 13111213129969. The next prime is 13111213130117. The reversal of 13111213130011 is 11003131211131.

13111213130011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (11003131211131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111213130011 - 2²⁹ = 13110676259099 is a prime.

It is not a weakly prime, because it can be changed into another prime (13111213130311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555606565005 + 6555606565006.

It is an arithmetic number, because the mean of its divisors is an integer number (6555606565006).

Almost surely, 2^{13111213130011} is an apocalyptic number.

13111213130011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111213130011 is an equidigital number, since it uses as much as digits as its factorization.

13111213130011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 13111213130011 its reverse (11003131211131), we get a palindrome (24114344341142).

The spelling of 13111213130011 in words is "thirteen trillion, one hundred eleven billion, two hundred thirteen million, one hundred thirty thousand, eleven".