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13111223013022 = 26555611506511
BaseRepresentation
bin1011111011001011000111…
…0010100100111010011110
31201102102100200020000010011
42332302301302210322132
53204303241042404042
643515113535433434
72522153220535441
oct276626162447236
951372320200104
1013111223013022
1141a5490644672
12157906208587a
137414c9676464
1433482d809658
1517b0bdd13a17
hexbecb1ca4e9e

13111223013022 has 4 divisors (see below), whose sum is σ = 19666834519536. Its totient is φ = 6555611506510.

The previous prime is 13111223013019. The next prime is 13111223013067. The reversal of 13111223013022 is 22031032211131.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13111223012984 and 13111223013002.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3277805753254 + ... + 3277805753257.

It is an arithmetic number, because the mean of its divisors is an integer number (4916708629884).

Almost surely, 213111223013022 is an apocalyptic number.

13111223013022 is a deficient number, since it is larger than the sum of its proper divisors (6555611506514).

13111223013022 is an equidigital number, since it uses as much as digits as its factorization.

13111223013022 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6555611506513.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 13111223013022 its reverse (22031032211131), we get a palindrome (35142255224153).

The spelling of 13111223013022 in words is "thirteen trillion, one hundred eleven billion, two hundred twenty-three million, thirteen thousand, twenty-two".

Divisors: 1 2 6555611506511 13111223013022