13111244121301 has 4 divisors (see below), whose sum is σ = 13167515555532. Its totient is φ = 13054972687072.

The previous prime is 13111244121271. The next prime is 13111244121329. The reversal of 13111244121301 is 10312144211131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3376681880625 + 9734562240676 = 1837575^2 + 3120026^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111244121301 - 2²¹ = 13111242024149 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111244121341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28135716766 + ... + 28135717231.

It is an arithmetic number, because the mean of its divisors is an integer number (3291878888883).

Almost surely, 2^{13111244121301} is an apocalyptic number.

It is an amenable number.

13111244121301 is a deficient number, since it is larger than the sum of its proper divisors (56271434231).

13111244121301 is an equidigital number, since it uses as much as digits as its factorization.

13111244121301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56271434230.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 13111244121301 its reverse (10312144211131), we get a palindrome (23423388332432).

The spelling of 13111244121301 in words is "thirteen trillion, one hundred eleven billion, two hundred forty-four million, one hundred twenty-one thousand, three hundred one".