Base | Representation |
---|---|
bin | 100111000100110… |
… | …0100000110110001 |
3 | 10101101010022021121 |
4 | 1032021210012301 |
5 | 10141122130113 |
6 | 334034022241 |
7 | 44330264353 |
oct | 11611440661 |
9 | 3341108247 |
10 | 1311130033 |
11 | 61310a444 |
12 | 307117981 |
13 | 17b833cb5 |
14 | c61bb0d3 |
15 | 7a18ce8d |
hex | 4e2641b1 |
1311130033 has 2 divisors, whose sum is σ = 1311130034. Its totient is φ = 1311130032.
The previous prime is 1311130013. The next prime is 1311130043. The reversal of 1311130033 is 3300311131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1310946849 + 183184 = 36207^2 + 428^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311130033 - 217 = 1310998961 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1311129989 and 1311130016.
It is not a weakly prime, because it can be changed into another prime (1311130013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655565016 + 655565017.
It is an arithmetic number, because the mean of its divisors is an integer number (655565017).
Almost surely, 21311130033 is an apocalyptic number.
It is an amenable number.
1311130033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311130033 is an equidigital number, since it uses as much as digits as its factorization.
1311130033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 16.
The square root of 1311130033 is about 36209.5295882175. The cubic root of 1311130033 is about 1094.4987128826.
Adding to 1311130033 its reverse (3300311131), we get a palindrome (4611441164).
The spelling of 1311130033 in words is "one billion, three hundred eleven million, one hundred thirty thousand, thirty-three".
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