Base | Representation |
---|---|
bin | 111101000011011110… |
… | …0011100100000000011 |
3 | 110112102111021001221222 |
4 | 1322012330130200003 |
5 | 4122004412324303 |
6 | 140122114505255 |
7 | 12321050130656 |
oct | 1720674344003 |
9 | 415374231858 |
10 | 131113011203 |
11 | 506719709a9 |
12 | 214b159522b |
13 | c49665c845 |
14 | 64bb23389d |
15 | 3625919938 |
hex | 1e86f1c803 |
131113011203 has 2 divisors, whose sum is σ = 131113011204. Its totient is φ = 131113011202.
The previous prime is 131113011199. The next prime is 131113011259. The reversal of 131113011203 is 302110311131.
It is a weak prime.
It is an emirp because it is prime and its reverse (302110311131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131113011203 - 22 = 131113011199 is a prime.
It is not a weakly prime, because it can be changed into another prime (131113011103) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65556505601 + 65556505602.
It is an arithmetic number, because the mean of its divisors is an integer number (65556505602).
Almost surely, 2131113011203 is an apocalyptic number.
131113011203 is a deficient number, since it is larger than the sum of its proper divisors (1).
131113011203 is an equidigital number, since it uses as much as digits as its factorization.
131113011203 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 131113011203 its reverse (302110311131), we get a palindrome (433223322334).
The spelling of 131113011203 in words is "one hundred thirty-one billion, one hundred thirteen million, eleven thousand, two hundred three".
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