Base | Representation |
---|---|
bin | 11000011010111111… |
… | …01001010001110001 |
3 | 1020211202020010001101 |
4 | 30031133221101301 |
5 | 203322443114413 |
6 | 10005004404401 |
7 | 642624136012 |
oct | 141537512161 |
9 | 36752203041 |
10 | 13111301233 |
11 | 5618a95748 |
12 | 265ab46701 |
13 | 130c471414 |
14 | 8c545d009 |
15 | 51b0d9edd |
hex | 30d7e9471 |
13111301233 has 2 divisors, whose sum is σ = 13111301234. Its totient is φ = 13111301232.
The previous prime is 13111301219. The next prime is 13111301237. The reversal of 13111301233 is 33210311131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 7309737009 + 5801564224 = 85497^2 + 76168^2 .
It is a cyclic number.
It is not a de Polignac number, because 13111301233 - 25 = 13111301201 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13111301233.
It is not a weakly prime, because it can be changed into another prime (13111301237) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555650616 + 6555650617.
It is an arithmetic number, because the mean of its divisors is an integer number (6555650617).
Almost surely, 213111301233 is an apocalyptic number.
It is an amenable number.
13111301233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111301233 is an equidigital number, since it uses as much as digits as its factorization.
13111301233 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13111301233 its reverse (33210311131), we get a palindrome (46321612364).
The spelling of 13111301233 in words is "thirteen billion, one hundred eleven million, three hundred one thousand, two hundred thirty-three".
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