13111304024111 has 4 divisors (see below), whose sum is σ = 13111858835712. Its totient is φ = 13110749212512.

The previous prime is 13111304024099. The next prime is 13111304024239. The reversal of 13111304024111 is 11142040311131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13111304024111 - 2¹⁰ = 13111304023087 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111304024711) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 277370351 + ... + 277417616.

It is an arithmetic number, because the mean of its divisors is an integer number (3277964708928).

Almost surely, 2^{13111304024111} is an apocalyptic number.

13111304024111 is a deficient number, since it is larger than the sum of its proper divisors (554811601).

13111304024111 is an equidigital number, since it uses as much as digits as its factorization.

13111304024111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 554811600.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 13111304024111 its reverse (11142040311131), we get a palindrome (24253344335242).

The spelling of 13111304024111 in words is "thirteen trillion, one hundred eleven billion, three hundred four million, twenty-four thousand, one hundred eleven".