11142040311131 has 2 divisors, whose sum is σ = 11142040311132. Its totient is φ = 11142040311130.

The previous prime is 11142040311113. The next prime is 11142040311191. The reversal of 11142040311131 is 13111304024111.

11142040311131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (11142040311113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 11142040311131 - 2³⁰ = 11140966569307 is a prime.

It is a super-2 number, since 2×11142040311131² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11142040311097 and 11142040311106.

It is not a weakly prime, because it can be changed into another prime (11142040311191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5571020155565 + 5571020155566.

It is an arithmetic number, because the mean of its divisors is an integer number (5571020155566).

Almost surely, 2^{11142040311131} is an apocalyptic number.

11142040311131 is a deficient number, since it is larger than the sum of its proper divisors (1).

11142040311131 is an equidigital number, since it uses as much as digits as its factorization.

11142040311131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 11142040311131 its reverse (13111304024111), we get a palindrome (24253344335242).

The spelling of 11142040311131 in words is "eleven trillion, one hundred forty-two billion, forty million, three hundred eleven thousand, one hundred thirty-one".