| Base | Representation |
|---|---|
| bin | 11101110011111100100101… |
| … | …110100011000000011100000 |
| 3 | 122012020021211110011111222200 |
| 4 | 131303330211310120003200 |
| 5 | 114141124112342211000 |
| 6 | 1142504305510133200 |
| 7 | 36421415605212231 |
| oct | 3563744564300340 |
| 9 | 565207743144880 |
| 10 | 131113101132000 |
| 11 | 3885a832528639 |
| 12 | 12856720351200 |
| 13 | 5820bb2680c70 |
| 14 | 2453c9d5d9088 |
| 15 | 10258452c6500 |
| hex | 773f25d180e0 |
131113101132000 has 576 divisors, whose sum is σ = 507457634261760. Its totient is φ = 31865453568000.
The previous prime is 131113101131989. The next prime is 131113101132007. The reversal of 131113101132000 is 231101311131.
131113101132000 is a `hidden beast` number, since 1 + 31 + 1 + 1 + 310 + 1 + 1 + 320 + 0 + 0 = 666.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131113101132007) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 35198860 + ... + 38745140.
It is an arithmetic number, because the mean of its divisors is an integer number (881002837260).
Almost surely, 2131113101132000 is an apocalyptic number.
131113101132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131113101132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (253728817130880).
131113101132000 is an abundant number, since it is smaller than the sum of its proper divisors (376344533129760).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131113101132000 is a wasteful number, since it uses less digits than its factorization.
131113101132000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3546404 (or 3546383 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 18.
Adding to 131113101132000 its reverse (231101311131), we get a palindrome (131344202443131).
The spelling of 131113101132000 in words is "one hundred thirty-one trillion, one hundred thirteen billion, one hundred one million, one hundred thirty-two thousand".
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