Base | Representation |
---|---|
bin | 1011111011001011011100… |
… | …0000000111110110111011 |
3 | 1201102102120202202021020201 |
4 | 2332302313000013312323 |
5 | 3204303430433400412 |
6 | 43515130341503031 |
7 | 2522155331665162 |
oct | 276626700076673 |
9 | 51372522667221 |
10 | 13111310450107 |
11 | 41a5525a35421 |
12 | 1579087411a77 |
13 | 74151180b98c |
14 | 33483b28a3d9 |
15 | 17b0c6835e57 |
hex | becb7007dbb |
13111310450107 has 2 divisors, whose sum is σ = 13111310450108. Its totient is φ = 13111310450106.
The previous prime is 13111310450033. The next prime is 13111310450153. The reversal of 13111310450107 is 70105401311131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13111310450107 is a prime.
It is a super-2 number, since 2×131113104501072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13111310453107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555655225053 + 6555655225054.
It is an arithmetic number, because the mean of its divisors is an integer number (6555655225054).
Almost surely, 213111310450107 is an apocalyptic number.
13111310450107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111310450107 is an equidigital number, since it uses as much as digits as its factorization.
13111310450107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1260, while the sum is 28.
Adding to 13111310450107 its reverse (70105401311131), we get a palindrome (83216711761238).
The spelling of 13111310450107 in words is "thirteen trillion, one hundred eleven billion, three hundred ten million, four hundred fifty thousand, one hundred seven".
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