1311131114 has 4 divisors (see below), whose sum is σ = 1966696674. Its totient is φ = 655565556.

The previous prime is 1311131111. The next prime is 1311131117. The reversal of 1311131114 is 4111311131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (1311131111) and next prime (1311131117).

It can be written as a sum of positive squares in only one way, i.e., 1309354225 + 1776889 = 36185^2 + 1333^2 .

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1311131092 and 1311131101.

It is not an unprimeable number, because it can be changed into a prime (1311131111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327782777 + ... + 327782780.

Almost surely, 2^1311131114 is an apocalyptic number.

1311131114 is a deficient number, since it is larger than the sum of its proper divisors (655565560).

1311131114 is an equidigital number, since it uses as much as digits as its factorization.

1311131114 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 655565559.

The product of its digits is 36, while the sum is 17.

The square root of 1311131114 is about 36209.5445152242. The cubic root of 1311131114 is about 1094.4990136799.

Adding to 1311131114 its reverse (4111311131), we get a palindrome (5422442245).

The spelling of 1311131114 in words is "one billion, three hundred eleven million, one hundred thirty-one thousand, one hundred fourteen".