131113201301233 has 4 divisors (see below), whose sum is σ = 132411351809268. Its totient is φ = 129815050793200.

The previous prime is 131113201301227. The next prime is 131113201301239. The reversal of 131113201301233 is 332103102311131.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (131113201301227) and next prime (131113201301239).

It can be written as a sum of positive squares in 2 ways, for example, as 65961312425649 + 65151888875584 = 8121657^2 + 8071672^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131113201301233 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131113201301198 and 131113201301207.

It is not an unprimeable number, because it can be changed into a prime (131113201301239) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 649075253866 + ... + 649075254067.

It is an arithmetic number, because the mean of its divisors is an integer number (33102837952317).

Almost surely, 2^{131113201301233} is an apocalyptic number.

It is an amenable number.

131113201301233 is a deficient number, since it is larger than the sum of its proper divisors (1298150508035).

131113201301233 is a wasteful number, since it uses less digits than its factorization.

131113201301233 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1298150508034.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 131113201301233 its reverse (332103102311131), we get a palindrome (463216303612364).

The spelling of 131113201301233 in words is "one hundred thirty-one trillion, one hundred thirteen billion, two hundred one million, three hundred one thousand, two hundred thirty-three".