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13111322999993 is a prime number
BaseRepresentation
bin1011111011001011011110…
…1111111111110010111001
31201102102121122100212110022
42332302313233333302321
53204303442141444433
643515131510500225
72522155543444601
oct276626757776271
951372548325408
1013111322999993
1141a5532027329
12157908b664675
137415142b404a
1433483cbd5c01
1517b0c79b4698
hexbecb7bffcb9

13111322999993 has 2 divisors, whose sum is σ = 13111322999994. Its totient is φ = 13111322999992.

The previous prime is 13111322999947. The next prime is 13111323000049. The reversal of 13111322999993 is 39999922311131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10452114418729 + 2659208581264 = 3232973^2 + 1630708^2 .

It is an emirp because it is prime and its reverse (39999922311131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111322999993 - 228 = 13111054564537 is a prime.

It is not a weakly prime, because it can be changed into another prime (13111322959993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555661499996 + 6555661499997.

It is an arithmetic number, because the mean of its divisors is an integer number (6555661499997).

Almost surely, 213111322999993 is an apocalyptic number.

It is an amenable number.

13111322999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111322999993 is an equidigital number, since it uses as much as digits as its factorization.

13111322999993 is an evil number, because the sum of its binary digits is even.

The product of its digits is 6377292, while the sum is 62.

The spelling of 13111322999993 in words is "thirteen trillion, one hundred eleven billion, three hundred twenty-two million, nine hundred ninety-nine thousand, nine hundred ninety-three".