131113230111341 has 4 divisors (see below), whose sum is σ = 132464912896092. Its totient is φ = 129761547326592.

The previous prime is 131113230111307. The next prime is 131113230111421. The reversal of 131113230111341 is 143111032311131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 77954242888900 + 53158987222441 = 8829170^2 + 7291021^2 .

It is a cyclic number.

It is not a de Polignac number, because 131113230111341 - 2³⁰ = 131112156369517 is a prime.

It is a super-2 number, since 2×131113230111341² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131113230111341.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131113230111301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 675841392230 + ... + 675841392423.

It is an arithmetic number, because the mean of its divisors is an integer number (33116228224023).

Almost surely, 2^{131113230111341} is an apocalyptic number.

It is an amenable number.

131113230111341 is a deficient number, since it is larger than the sum of its proper divisors (1351682784751).

131113230111341 is an equidigital number, since it uses as much as digits as its factorization.

131113230111341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1351682784750.

The product of its (nonzero) digits is 648, while the sum is 26.

Adding to 131113230111341 its reverse (143111032311131), we get a palindrome (274224262422472).

The spelling of 131113230111341 in words is "one hundred thirty-one trillion, one hundred thirteen billion, two hundred thirty million, one hundred eleven thousand, three hundred forty-one".