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131113230333 = 3312890148781
BaseRepresentation
bin111101000011011110…
…1010001111111111101
3110112102111200012112220
41322012331101333331
54122004441332313
6140122123315553
712321052032561
oct1720675217775
9415374605486
10131113230333
11506720005a8
12214b167bbb9
13c4967084c7
1464bb28d6a1
15362595e823
hex1e86f51ffd

131113230333 has 16 divisors (see below), whose sum is σ = 180466862592. Its totient is φ = 84584520000.

The previous prime is 131113230331. The next prime is 131113230341. The reversal of 131113230333 is 333032311131.

It is not a de Polignac number, because 131113230333 - 21 = 131113230331 is a prime.

It is a super-2 number, since 2×1311132303332 (a number of 23 digits) contains 22 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131113230331) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2663403 + ... + 2712183.

It is an arithmetic number, because the mean of its divisors is an integer number (11279178912).

Almost surely, 2131113230333 is an apocalyptic number.

It is an amenable number.

131113230333 is a deficient number, since it is larger than the sum of its proper divisors (49353632259).

131113230333 is a wasteful number, since it uses less digits than its factorization.

131113230333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 77716.

The product of its (nonzero) digits is 1458, while the sum is 24.

Adding to 131113230333 its reverse (333032311131), we get a palindrome (464145541464).

The spelling of 131113230333 in words is "one hundred thirty-one billion, one hundred thirteen million, two hundred thirty thousand, three hundred thirty-three".

Divisors: 1 3 31 93 28901 48781 86703 146343 895931 1512211 2687793 4536633 1409819681 4229459043 43704410111 131113230333