Base | Representation |
---|---|
bin | 111101000011011110… |
… | …1101000001100010001 |
3 | 110112102111211211020120 |
4 | 1322012331220030101 |
5 | 4122010002234413 |
6 | 140122125300453 |
7 | 12321052561566 |
oct | 1720675501421 |
9 | 415374754216 |
10 | 131113321233 |
11 | 50672062924 |
12 | 214b1704729 |
13 | c49673a9ab |
14 | 64bb2b486d |
15 | 362597b723 |
hex | 1e86f68311 |
131113321233 has 4 divisors (see below), whose sum is σ = 174817761648. Its totient is φ = 87408880820.
The previous prime is 131113321217. The next prime is 131113321247. The reversal of 131113321233 is 332123311131.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 332123311131 = 3 ⋅110707770377.
It is a cyclic number.
It is not a de Polignac number, because 131113321233 - 24 = 131113321217 is a prime.
It is not an unprimeable number, because it can be changed into a prime (131113321333) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21852220203 + ... + 21852220208.
It is an arithmetic number, because the mean of its divisors is an integer number (43704440412).
Almost surely, 2131113321233 is an apocalyptic number.
It is an amenable number.
131113321233 is a deficient number, since it is larger than the sum of its proper divisors (43704440415).
131113321233 is an equidigital number, since it uses as much as digits as its factorization.
131113321233 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 43704440414.
The product of its digits is 972, while the sum is 24.
Adding to 131113321233 its reverse (332123311131), we get a palindrome (463236632364).
The spelling of 131113321233 in words is "one hundred thirty-one billion, one hundred thirteen million, three hundred twenty-one thousand, two hundred thirty-three".
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