Base | Representation |
---|---|
bin | 1011111011001011100001… |
… | …0011001101001111000011 |
3 | 1201102102122021201210202111 |
4 | 2332302320103031033003 |
5 | 3204304002022330313 |
6 | 43515132440400151 |
7 | 2522156015056513 |
oct | 276627023151703 |
9 | 51372567653674 |
10 | 13111332230083 |
11 | 41a5537260aaa |
12 | 1579092776057 |
13 | 741516196339 |
14 | 334840119843 |
15 | 17b0c86d943d |
hex | becb84cd3c3 |
13111332230083 has 2 divisors, whose sum is σ = 13111332230084. Its totient is φ = 13111332230082.
The previous prime is 13111332230069. The next prime is 13111332230111. The reversal of 13111332230083 is 38003223311131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13111332230083 - 213 = 13111332221891 is a prime.
It is a super-2 number, since 2×131113322300832 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13111332230033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555666115041 + 6555666115042.
It is an arithmetic number, because the mean of its divisors is an integer number (6555666115042).
Almost surely, 213111332230083 is an apocalyptic number.
13111332230083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111332230083 is an equidigital number, since it uses as much as digits as its factorization.
13111332230083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
The spelling of 13111332230083 in words is "thirteen trillion, one hundred eleven billion, three hundred thirty-two million, two hundred thirty thousand, eighty-three".
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