Base | Representation |
---|---|
bin | 111101000011100000… |
… | …0010101010000100111 |
3 | 110112102120011211122121 |
4 | 1322013000111100213 |
5 | 4122010142430434 |
6 | 140122152410411 |
7 | 12321061603402 |
oct | 1720700252047 |
9 | 415376154577 |
10 | 131114030119 |
11 | 506724a7486 |
12 | 214b19a6a07 |
13 | c496928557 |
14 | 64bb41ad39 |
15 | 3625a6b7b4 |
hex | 1e87015427 |
131114030119 has 8 divisors (see below), whose sum is σ = 138830046768. Its totient is φ = 123398394240.
The previous prime is 131114030077. The next prime is 131114030149. The reversal of 131114030119 is 911030411131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 131114030119 - 217 = 131113899047 is a prime.
It is a super-2 number, since 2×1311140301192 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131114030093 and 131114030102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131114030149) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 928164 + ... + 1060054.
It is an arithmetic number, because the mean of its divisors is an integer number (17353755846).
Almost surely, 2131114030119 is an apocalyptic number.
131114030119 is a deficient number, since it is larger than the sum of its proper divisors (7716016649).
131114030119 is a wasteful number, since it uses less digits than its factorization.
131114030119 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 190385.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 131114030119 in words is "one hundred thirty-one billion, one hundred fourteen million, thirty thousand, one hundred nineteen".
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