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1311140410222 = 21891734655083
BaseRepresentation
bin10011000101000110000…
…011101111001101101110
311122100021121222221002011
4103011012003233031232
5132440203421111342
62442155105151434
7163504165413436
oct23050603571556
94570247887064
101311140410222
11466062642295
1219213632b57a
1396842143a56
1447660d692c6
152418be9c717
hex131460ef36e

1311140410222 has 8 divisors (see below), whose sum is σ = 1966814637336. Its totient is φ = 655535531112.

The previous prime is 1311140410081. The next prime is 1311140410243. The reversal of 1311140410222 is 2220140411131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13111404102222 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311140410193 and 1311140410202.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17289708 + ... + 17365375.

It is an arithmetic number, because the mean of its divisors is an integer number (245851829667).

Almost surely, 21311140410222 is an apocalyptic number.

1311140410222 is a deficient number, since it is larger than the sum of its proper divisors (655674227114).

1311140410222 is a wasteful number, since it uses less digits than its factorization.

1311140410222 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 34674002.

The product of its (nonzero) digits is 384, while the sum is 22.

Adding to 1311140410222 its reverse (2220140411131), we get a palindrome (3531280821353).

Subtracting 1311140410222 from its reverse (2220140411131), we obtain a palindrome (909000000909).

The spelling of 1311140410222 in words is "one trillion, three hundred eleven billion, one hundred forty million, four hundred ten thousand, two hundred twenty-two".

Divisors: 1 2 18917 37834 34655083 69310166 655570205111 1311140410222