131114114423213 has 4 divisors (see below), whose sum is σ = 131314901735388. Its totient is φ = 130913327111040.

The previous prime is 131114114423113. The next prime is 131114114423219. The reversal of 131114114423213 is 312324411411131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 51265557040009 + 79848557383204 = 7159997^2 + 8935802^2 .

It is a cyclic number.

It is not a de Polignac number, because 131114114423213 - 2⁸ = 131114114422957 is a prime.

It is a super-2 number, since 2×131114114423213² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 131114114423213.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131114114423219) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 100393655108 + ... + 100393656413.

It is an arithmetic number, because the mean of its divisors is an integer number (32828725433847).

Almost surely, 2^{131114114423213} is an apocalyptic number.

It is an amenable number.

131114114423213 is a deficient number, since it is larger than the sum of its proper divisors (200787312175).

131114114423213 is an equidigital number, since it uses as much as digits as its factorization.

131114114423213 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 200787312174.

The product of its digits is 6912, while the sum is 32.

Adding to 131114114423213 its reverse (312324411411131), we get a palindrome (443438525834344).

The spelling of 131114114423213 in words is "one hundred thirty-one trillion, one hundred fourteen billion, one hundred fourteen million, four hundred twenty-three thousand, two hundred thirteen".