131114141010141 has 4 divisors (see below), whose sum is σ = 174818854680192. Its totient is φ = 87409427340092.

The previous prime is 131114141010113. The next prime is 131114141010143. The reversal of 131114141010141 is 141010141411131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 131114141010141 - 2¹⁴ = 131114140993757 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131114141010143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21852356835021 + ... + 21852356835026.

It is an arithmetic number, because the mean of its divisors is an integer number (43704713670048).

Almost surely, 2^{131114141010141} is an apocalyptic number.

It is an amenable number.

131114141010141 is a deficient number, since it is larger than the sum of its proper divisors (43704713670051).

131114141010141 is an equidigital number, since it uses as much as digits as its factorization.

131114141010141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43704713670050.

The product of its (nonzero) digits is 192, while the sum is 24.

Adding to 131114141010141 its reverse (141010141411131), we get a palindrome (272124282421272).

The spelling of 131114141010141 in words is "one hundred thirty-one trillion, one hundred fourteen billion, one hundred forty-one million, ten thousand, one hundred forty-one".