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1311142114 = 2655571057
BaseRepresentation
bin100111000100110…
…0111000011100010
310101101010220212001
41032021213003202
510141123021424
6334034154214
744330344522
oct11611470342
93341126761
101311142114
11613118527
1230712296a
1317b839649
14c61c1682
157a191844
hex4e2670e2

1311142114 has 4 divisors (see below), whose sum is σ = 1966713174. Its totient is φ = 655571056.

The previous prime is 1311142109. The next prime is 1311142121. The reversal of 1311142114 is 4112411131.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 4112411131 = 37910850689.

It can be written as a sum of positive squares in only one way, i.e., 659616489 + 651525625 = 25683^2 + 25525^2 .

It is a junction number, because it is equal to n+sod(n) for n = 1311142091 and 1311142100.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 327785527 + ... + 327785530.

Almost surely, 21311142114 is an apocalyptic number.

1311142114 is a deficient number, since it is larger than the sum of its proper divisors (655571060).

1311142114 is an equidigital number, since it uses as much as digits as its factorization.

1311142114 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 655571059.

The product of its digits is 96, while the sum is 19.

The square root of 1311142114 is about 36209.6964085589. The cubic root of 1311142114 is about 1094.5020745117.

Adding to 1311142114 its reverse (4112411131), we get a palindrome (5423553245).

It can be divided in two parts, 13111 and 42114, that added together give a square (55225 = 2352).

The spelling of 1311142114 in words is "one billion, three hundred eleven million, one hundred forty-two thousand, one hundred fourteen".

Divisors: 1 2 655571057 1311142114