131114244031 has 4 divisors (see below), whose sum is σ = 134312152464. Its totient is φ = 127916335600.

The previous prime is 131114244007. The next prime is 131114244043. The reversal of 131114244031 is 130442411131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 131114244031 - 2⁷ = 131114243903 is a prime.

It is a super-2 number, since 2×131114244031² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131114243987 and 131114244005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131114244731) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1598954155 + ... + 1598954236.

It is an arithmetic number, because the mean of its divisors is an integer number (33578038116).

Almost surely, 2^131114244031 is an apocalyptic number.

131114244031 is a deficient number, since it is larger than the sum of its proper divisors (3197908433).

131114244031 is an equidigital number, since it uses as much as digits as its factorization.

131114244031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3197908432.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 131114244031 its reverse (130442411131), we get a palindrome (261556655162).

The spelling of 131114244031 in words is "one hundred thirty-one billion, one hundred fourteen million, two hundred forty-four thousand, thirty-one".