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13111431554332 = 2222371465291859
BaseRepresentation
bin1011111011001011111000…
…1110000110010100011100
31201102102220012122000000101
42332302332032012110130
53204304202434214312
643515150345310444
72522161332235546
oct276627616062434
951372805560011
1013111431554332
1141a5588330861
1215790bba95424
13741530931397
1433484d3b2696
1517b0d22a8a57
hexbecbe38651c

13111431554332 has 12 divisors (see below), whose sum is σ = 22955262278760. Its totient is φ = 6552785188976.

The previous prime is 13111431554323. The next prime is 13111431554461. The reversal of 13111431554332 is 23345513411131.

It is a super-3 number, since 3×131114315543323 (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13111431554291 and 13111431554300.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 732636982 + ... + 732654877.

It is an arithmetic number, because the mean of its divisors is an integer number (1912938523230).

Almost surely, 213111431554332 is an apocalyptic number.

It is an amenable number.

13111431554332 is a deficient number, since it is larger than the sum of its proper divisors (9843830724428).

13111431554332 is a wasteful number, since it uses less digits than its factorization.

13111431554332 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1465294100 (or 1465294098 counting only the distinct ones).

The product of its digits is 64800, while the sum is 37.

Adding to 13111431554332 its reverse (23345513411131), we get a palindrome (36456944965463).

The spelling of 13111431554332 in words is "thirteen trillion, one hundred eleven billion, four hundred thirty-one million, five hundred fifty-four thousand, three hundred thirty-two".

Divisors: 1 2 4 2237 4474 8948 1465291859 2930583718 5861167436 3277857888583 6555715777166 13111431554332