Base | Representation |
---|---|
bin | 1011111011001100001010… |
… | …0111001010000011010011 |
3 | 1201102110002100021012212222 |
4 | 2332303002213022003103 |
5 | 3204304330314411313 |
6 | 43515201540411255 |
7 | 2522163215420516 |
oct | 276630247120323 |
9 | 51373070235788 |
10 | 13111505232083 |
11 | 41a5615983a65 |
12 | 15791206a6b2b |
13 | 741542c89b9b |
14 | 3348590b0d7d |
15 | 17b0d89ae208 |
hex | becc29ca0d3 |
13111505232083 has 2 divisors, whose sum is σ = 13111505232084. Its totient is φ = 13111505232082.
The previous prime is 13111505232037. The next prime is 13111505232097. The reversal of 13111505232083 is 38023250511131.
13111505232083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111505232083 - 26 = 13111505232019 is a prime.
It is not a weakly prime, because it can be changed into another prime (13111505234083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555752616041 + 6555752616042.
It is an arithmetic number, because the mean of its divisors is an integer number (6555752616042).
Almost surely, 213111505232083 is an apocalyptic number.
13111505232083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111505232083 is an equidigital number, since it uses as much as digits as its factorization.
13111505232083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 35.
The spelling of 13111505232083 in words is "thirteen trillion, one hundred eleven billion, five hundred five million, two hundred thirty-two thousand, eighty-three".
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