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131115201552353 = 1313498873233201
BaseRepresentation
bin11101110011111110100011…
…000000110101111111100001
3122012020111020211110221001002
4131303332203000311333201
5114141142413044133403
61142505254141321345
736421521631406564
oct3563764300657741
9565214224427032
10131115201552353
1138860710123527
1212857007866255
135821158888245
14245401c5544db
1510259198c3188
hex773fa3035fe1

131115201552353 has 16 divisors (see below), whose sum is σ = 132644051971200. Its totient is φ = 129595191648000.

The previous prime is 131115201552347. The next prime is 131115201552373. The reversal of 131115201552353 is 353255102511131.

It is a cyclic number.

It is not a de Polignac number, because 131115201552353 - 24 = 131115201552337 is a prime.

It is a super-2 number, since 2×1311152015523532 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (131115201552373) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 38936153 + ... + 42169353.

It is an arithmetic number, because the mean of its divisors is an integer number (8290253248200).

Almost surely, 2131115201552353 is an apocalyptic number.

It is an amenable number.

131115201552353 is a deficient number, since it is larger than the sum of its proper divisors (1528850418847).

131115201552353 is a wasteful number, since it uses less digits than its factorization.

131115201552353 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3234568.

The product of its (nonzero) digits is 67500, while the sum is 38.

The spelling of 131115201552353 in words is "one hundred thirty-one trillion, one hundred fifteen billion, two hundred one million, five hundred fifty-two thousand, three hundred fifty-three".

Divisors: 1 131 349 887 45719 116197 309563 3233201 40552753 423549331 1128387149 2867849287 147818716519 375688256597 1000879401163 131115201552353