131115312115451 has 2 divisors, whose sum is σ = 131115312115452. Its totient is φ = 131115312115450.

The previous prime is 131115312115429. The next prime is 131115312115471. The reversal of 131115312115451 is 154511213511131.

It is a strong prime.

It is an emirp because it is prime and its reverse (154511213511131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131115312115451 - 2¹⁰ = 131115312114427 is a prime.

It is a super-3 number, since 3×131115312115451³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (131115312115471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65557656057725 + 65557656057726.

It is an arithmetic number, because the mean of its divisors is an integer number (65557656057726).

Almost surely, 2^{131115312115451} is an apocalyptic number.

131115312115451 is a deficient number, since it is larger than the sum of its proper divisors (1).

131115312115451 is an equidigital number, since it uses as much as digits as its factorization.

131115312115451 is an evil number, because the sum of its binary digits is even.

The product of its digits is 9000, while the sum is 35.

Adding to 131115312115451 its reverse (154511213511131), we get a palindrome (285626525626582).

The spelling of 131115312115451 in words is "one hundred thirty-one trillion, one hundred fifteen billion, three hundred twelve million, one hundred fifteen thousand, four hundred fifty-one".