Base | Representation |
---|---|
bin | 11000011011000010… |
… | …10100010010010011 |
3 | 1020211210001101021221 |
4 | 30031201110102103 |
5 | 203323101131124 |
6 | 10005022025511 |
7 | 642630642613 |
oct | 141541242223 |
9 | 36753041257 |
10 | 13111739539 |
11 | 5619264a88 |
12 | 265b118297 |
13 | 130c595a82 |
14 | 8c5534a43 |
15 | 51b174ce4 |
hex | 30d854493 |
13111739539 has 2 divisors, whose sum is σ = 13111739540. Its totient is φ = 13111739538.
The previous prime is 13111739471. The next prime is 13111739569. The reversal of 13111739539 is 93593711131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111739539 - 215 = 13111706771 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13111739495 and 13111739504.
It is not a weakly prime, because it can be changed into another prime (13111739569) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555869769 + 6555869770.
It is an arithmetic number, because the mean of its divisors is an integer number (6555869770).
Almost surely, 213111739539 is an apocalyptic number.
13111739539 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111739539 is an equidigital number, since it uses as much as digits as its factorization.
13111739539 is an evil number, because the sum of its binary digits is even.
The product of its digits is 76545, while the sum is 43.
The spelling of 13111739539 in words is "thirteen billion, one hundred eleven million, seven hundred thirty-nine thousand, five hundred thirty-nine".
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