Search a number
-
+
13112001130302 = 232728444507239
BaseRepresentation
bin1011111011001110000000…
…1010110110111100111110
31201102111100220101110100200
42332303200022312330332
53204311334242132202
643515323053304330
72522211416452104
oct276634012667476
951374326343320
1013112001130302
1141a584a8996a8
12157923a7950a6
137415c1936c99
143348a4cb9c74
1517b1172b6e1c
hexbece02b6f3e

13112001130302 has 12 divisors (see below), whose sum is σ = 28409335782360. Its totient is φ = 4370667043428.

The previous prime is 13112001130289. The next prime is 13112001130303. The reversal of 13112001130302 is 20303110021131.

13112001130302 is a `hidden beast` number, since 1 + 31 + 1 + 200 + 1 + 130 + 302 = 666.

It is a super-2 number, since 2×131120011303022 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18), and also a Moran number because the ratio is a prime number: 728444507239 = 13112001130302 / (1 + 3 + 1 + 1 + 2 + 0 + 0 + 1 + 1 + 3 + 0 + 3 + 0 + 2).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13112001130303) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 364222253602 + ... + 364222253637.

It is an arithmetic number, because the mean of its divisors is an integer number (2367444648530).

Almost surely, 213112001130302 is an apocalyptic number.

13112001130302 is an abundant number, since it is smaller than the sum of its proper divisors (15297334652058).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112001130302 is a wasteful number, since it uses less digits than its factorization.

13112001130302 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 728444507247 (or 728444507244 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 13112001130302 its reverse (20303110021131), we get a palindrome (33415111151433).

The spelling of 13112001130302 in words is "thirteen trillion, one hundred twelve billion, one million, one hundred thirty thousand, three hundred two".

Divisors: 1 2 3 6 9 18 728444507239 1456889014478 2185333521717 4370667043434 6556000565151 13112001130302