Base | Representation |
---|---|
bin | 1011111011001110000101… |
… | …0010011010111110000011 |
3 | 1201102111102012200112220012 |
4 | 2332303201102122332003 |
5 | 3204311404042440201 |
6 | 43515325003335135 |
7 | 2522212035064205 |
oct | 276634122327603 |
9 | 51374365615805 |
10 | 13112019890051 |
11 | 41a585a442125 |
12 | 1579244b214ab |
13 | 7415c57a4a24 |
14 | 3348a75a0775 |
15 | 17b118c705bb |
hex | bece149af83 |
13112019890051 has 2 divisors, whose sum is σ = 13112019890052. Its totient is φ = 13112019890050.
The previous prime is 13112019890029. The next prime is 13112019890077. The reversal of 13112019890051 is 15009891021131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13112019890051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13112019889990 and 13112019890008.
It is not a weakly prime, because it can be changed into another prime (13112019890351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556009945025 + 6556009945026.
It is an arithmetic number, because the mean of its divisors is an integer number (6556009945026).
Almost surely, 213112019890051 is an apocalyptic number.
13112019890051 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112019890051 is an equidigital number, since it uses as much as digits as its factorization.
13112019890051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 19440, while the sum is 41.
The spelling of 13112019890051 in words is "thirteen trillion, one hundred twelve billion, nineteen million, eight hundred ninety thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •