Base | Representation |
---|---|
bin | 11101110100000011001101… |
… | …000010010010010110100001 |
3 | 122012020222011021211200001201 |
4 | 131310003031002102112201 |
5 | 114141233133043303100 |
6 | 1142511442232401201 |
7 | 36422056553536204 |
oct | 3564031502222641 |
9 | 565228137750051 |
10 | 131120201541025 |
11 | 38862846522a74 |
12 | 12857b82246201 |
13 | 5821774711918 |
14 | 245437461193b |
15 | 1025b0d82636a |
hex | 7740cd0925a1 |
131120201541025 has 24 divisors (see below), whose sum is σ = 172202314284000. Its totient is φ = 98697582255360.
The previous prime is 131120201540971. The next prime is 131120201541101. The reversal of 131120201541025 is 520145102021131.
It is not a de Polignac number, because 131120201541025 - 29 = 131120201540513 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131120201540984 and 131120201541002.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 42599539 + ... + 45573688.
It is an arithmetic number, because the mean of its divisors is an integer number (7175096428500).
Almost surely, 2131120201541025 is an apocalyptic number.
It is an amenable number.
131120201541025 is a deficient number, since it is larger than the sum of its proper divisors (41082112742975).
131120201541025 is a wasteful number, since it uses less digits than its factorization.
131120201541025 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88176753 (or 88176748 counting only the distinct ones).
The product of its (nonzero) digits is 2400, while the sum is 28.
Adding to 131120201541025 its reverse (520145102021131), we get a palindrome (651265303562156).
The spelling of 131120201541025 in words is "one hundred thirty-one trillion, one hundred twenty billion, two hundred one million, five hundred forty-one thousand, twenty-five".
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