Base | Representation |
---|---|
bin | 11101110100000011010011… |
… | …001010010111101110101001 |
3 | 122012020222102110020120002221 |
4 | 131310003103022113232221 |
5 | 114141233340401322442 |
6 | 1142511500343354041 |
7 | 36422062242300436 |
oct | 3564032312275651 |
9 | 565228373216087 |
10 | 131120304323497 |
11 | 38862899544a65 |
12 | 12857bb0752921 |
13 | 582178cabaa58 |
14 | 2454384128b8d |
15 | 1025b1787a467 |
hex | 7740d3297ba9 |
131120304323497 has 2 divisors, whose sum is σ = 131120304323498. Its totient is φ = 131120304323496.
The previous prime is 131120304323483. The next prime is 131120304323509. The reversal of 131120304323497 is 794323403021131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131072708792601 + 47595530896 = 11448699^2 + 218164^2 .
It is a cyclic number.
It is not a de Polignac number, because 131120304323497 - 223 = 131120295934889 is a prime.
It is not a weakly prime, because it can be changed into another prime (131120308323497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560152161748 + 65560152161749.
It is an arithmetic number, because the mean of its divisors is an integer number (65560152161749).
Almost surely, 2131120304323497 is an apocalyptic number.
It is an amenable number.
131120304323497 is a deficient number, since it is larger than the sum of its proper divisors (1).
131120304323497 is an equidigital number, since it uses as much as digits as its factorization.
131120304323497 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 326592, while the sum is 43.
The spelling of 131120304323497 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred four million, three hundred twenty-three thousand, four hundred ninety-seven".
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